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**A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?**

A. 4 litres, 8 litres
B. 6 litres, 6 litres
C. 5 litres, 7 litres
D. 7 litres, 5 litres
**Answer: Option B**

## Show Answer

Solution(By Apex Team)

Let the cost of 1 litre milk be Rs. 1
Milk in 1 litre mixture in 1st can = $\Large\frac{3}{4}$ litre, C.P. of 1 litre mixture in 1st can Rs.$\Large\frac{3}{4}$
Milk in 1 litre mixture in 2nd can = $\Large\frac{1}{2}$ litre, C.P. of 1 litre mixture in 2nd can Rs.$\Large\frac{1}{2}$
Milk in 1 litre of final mixture = $\Large\frac{5}{8}$ litre, Mean price = Rs.$\Large\frac{5}{8}$
By the rule of alligation, we have:
∴ Ratio of two mixtures = $\Large\frac{1}{8}: \frac{1}{8}$ = 1 : 1
So, quantity of mixture taken from each can = $\left(\large\frac{1}{2} \times 12\right)$ = 6 litres

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